Tuesday 26 April 2011

Form 4 - 2.2 Analysing Motion Graphs

 


 

Exercise 1 :

                              

Answers :
a)  Velocity = Gradient of graph = 15/3 = 5 m s-1
b)  Time = 10 – 3 = 7 s
c)   t = 15 s
d)  i)  Average speed = Distance/time = (15+15)/15 = 2 m s-1
     ii) Average velocity = Displacement/time = 0/15 = 0 m s-1


Exercise 2 : 



Answers :
a)   a = Gradient =(0-12)/(13-10) = -4  m s-2
      deceleration = 4 m s-2

b)  Displacement = area under the graph
                              = ½  x 12 x (4 + 13)
                              = 102 m northwards

c)  Time   = (20 – 15) = 5 s
d)  Area of triangle = ½ x 10 x 5 = 25 m
      Final displacement = 102 – 25 = 77 m towards the north.

e)   Average velocity = Final displacement / time
                               = 77 m / 20 s
                               = 3.85 m s -1    

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